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x^2-0.85x+0.005=0
a = 1; b = -0.85; c = +0.005;
Δ = b2-4ac
Δ = -0.852-4·1·0.005
Δ = 0.7025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.85)-\sqrt{0.7025}}{2*1}=\frac{0.85-\sqrt{0.7025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.85)+\sqrt{0.7025}}{2*1}=\frac{0.85+\sqrt{0.7025}}{2} $
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